(x-2)(x^2+2x+4)=0

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Solution for (x-2)(x^2+2x+4)=0 equation:


Simplifying
(x + -2)(x2 + 2x + 4) = 0

Reorder the terms:
(-2 + x)(x2 + 2x + 4) = 0

Reorder the terms:
(-2 + x)(4 + 2x + x2) = 0

Multiply (-2 + x) * (4 + 2x + x2)
(-2(4 + 2x + x2) + x(4 + 2x + x2)) = 0
((4 * -2 + 2x * -2 + x2 * -2) + x(4 + 2x + x2)) = 0
((-8 + -4x + -2x2) + x(4 + 2x + x2)) = 0
(-8 + -4x + -2x2 + (4 * x + 2x * x + x2 * x)) = 0
(-8 + -4x + -2x2 + (4x + 2x2 + x3)) = 0

Reorder the terms:
(-8 + -4x + 4x + -2x2 + 2x2 + x3) = 0

Combine like terms: -4x + 4x = 0
(-8 + 0 + -2x2 + 2x2 + x3) = 0
(-8 + -2x2 + 2x2 + x3) = 0

Combine like terms: -2x2 + 2x2 = 0
(-8 + 0 + x3) = 0
(-8 + x3) = 0

Solving
-8 + x3 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + x3 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + x3 = 0 + 8
x3 = 0 + 8

Combine like terms: 0 + 8 = 8
x3 = 8

Simplifying
x3 = 8

Reorder the terms:
-8 + x3 = 8 + -8

Combine like terms: 8 + -8 = 0
-8 + x3 = 0

The solution to this equation could not be determined.

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